Grab the TicWatch E and S for 30% off in Amazon Spring Sale

Ticwatch Pro is also on sale too
Big Ticwatch smartwatch deals live on Amazon
Wareable is reader-powered. If you click through using links on the site, we may earn an affiliate commission. Learn more

Amazon's Spring Sale is still rolling in the UK, and now a trio of Ticwatches have been added to the list of smartwatches you can get on the cheap.

You can currently pick up the TicWatch E and TicWatch S, which are both up to 30% off in the Spring Sale. The E is down to £112.79 from £140.99, while the S is now just £142.39 down from £177.99.

The smartwatch duo were launched in 2018 and have since been upgraded in the form of the TicWatch E2 and the S2, which do add the desirable feature of a fully waterproof design. But if jumping in the water with your smartwatch isn't that a big of a deal, these are still two really good value smartwatches if you don't want to spend big on something like an Apple Watch or a Samsung Galaxy Watch. You'll get those core smartwatch features and extras like a heart rate monitor and built-in GPS.

TicWatch E - 112.79
TicWatch E - 112.79

TicWatch S - £142.39
TicWatch S - £142.39

TicWatch Pro - £171.98
TicWatch Pro - £171.98

If you've had your eye on the TicWatch Pro, the good-looking smartwatch running on Google's Wear OS is also 20% off and can be grabbed for £171.98. That's down from £214.99 and a decent £43 saving. This deal covers both the silver and black versions that both come with a leather strap and features like built-in GPS, Google Pay and a battery life of up to 30 days (although a lot of that will be in low-power mode).


Amazon's Spring Sale is running now until the 15 April, and these deals are only available for 12 hours, so you've got a small window to decide whether you want in on these cheap smartwatches. While they're not the latest models, these smartwatches definitely get a thumbs-up from us.

Got any questions about the TicWatches on sale? Let us know in the comments section.





What do you think?
Reply to
Your comment